Optimal. Leaf size=140 \[ -\frac {A}{5 b^3 x^5}-\frac {b B-3 A c}{3 b^4 x^3}+\frac {3 c (b B-2 A c)}{b^5 x}+\frac {c^2 (b B-A c) x}{4 b^4 \left (b+c x^2\right )^2}+\frac {c^2 (11 b B-15 A c) x}{8 b^5 \left (b+c x^2\right )}+\frac {7 c^{3/2} (5 b B-9 A c) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {b}}\right )}{8 b^{11/2}} \]
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Rubi [A]
time = 0.22, antiderivative size = 140, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 5, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {1607, 467,
1819, 1816, 211} \begin {gather*} \frac {7 c^{3/2} (5 b B-9 A c) \text {ArcTan}\left (\frac {\sqrt {c} x}{\sqrt {b}}\right )}{8 b^{11/2}}+\frac {c^2 x (11 b B-15 A c)}{8 b^5 \left (b+c x^2\right )}+\frac {3 c (b B-2 A c)}{b^5 x}+\frac {c^2 x (b B-A c)}{4 b^4 \left (b+c x^2\right )^2}-\frac {b B-3 A c}{3 b^4 x^3}-\frac {A}{5 b^3 x^5} \end {gather*}
Antiderivative was successfully verified.
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Rule 211
Rule 467
Rule 1607
Rule 1816
Rule 1819
Rubi steps
\begin {align*} \int \frac {A+B x^2}{\left (b x^2+c x^4\right )^3} \, dx &=\int \frac {A+B x^2}{x^6 \left (b+c x^2\right )^3} \, dx\\ &=\frac {c^2 (b B-A c) x}{4 b^4 \left (b+c x^2\right )^2}-\frac {1}{4} c^2 \int \frac {-\frac {4 A}{b c^2}-\frac {4 (b B-A c) x^2}{b^2 c^2}+\frac {4 (b B-A c) x^4}{b^3 c}-\frac {3 (b B-A c) x^6}{b^4}}{x^6 \left (b+c x^2\right )^2} \, dx\\ &=\frac {c^2 (b B-A c) x}{4 b^4 \left (b+c x^2\right )^2}+\frac {c^2 (11 b B-15 A c) x}{8 b^5 \left (b+c x^2\right )}+\frac {c^2 \int \frac {\frac {8 A}{b c^2}+\frac {8 (b B-2 A c) x^2}{b^2 c^2}-\frac {8 (2 b B-3 A c) x^4}{b^3 c}+\frac {(11 b B-15 A c) x^6}{b^4}}{x^6 \left (b+c x^2\right )} \, dx}{8 b}\\ &=\frac {c^2 (b B-A c) x}{4 b^4 \left (b+c x^2\right )^2}+\frac {c^2 (11 b B-15 A c) x}{8 b^5 \left (b+c x^2\right )}+\frac {c^2 \int \left (\frac {8 A}{b^2 c^2 x^6}+\frac {8 (b B-3 A c)}{b^3 c^2 x^4}-\frac {24 (b B-2 A c)}{b^4 c x^2}+\frac {7 (5 b B-9 A c)}{b^4 \left (b+c x^2\right )}\right ) \, dx}{8 b}\\ &=-\frac {A}{5 b^3 x^5}-\frac {b B-3 A c}{3 b^4 x^3}+\frac {3 c (b B-2 A c)}{b^5 x}+\frac {c^2 (b B-A c) x}{4 b^4 \left (b+c x^2\right )^2}+\frac {c^2 (11 b B-15 A c) x}{8 b^5 \left (b+c x^2\right )}+\frac {\left (7 c^2 (5 b B-9 A c)\right ) \int \frac {1}{b+c x^2} \, dx}{8 b^5}\\ &=-\frac {A}{5 b^3 x^5}-\frac {b B-3 A c}{3 b^4 x^3}+\frac {3 c (b B-2 A c)}{b^5 x}+\frac {c^2 (b B-A c) x}{4 b^4 \left (b+c x^2\right )^2}+\frac {c^2 (11 b B-15 A c) x}{8 b^5 \left (b+c x^2\right )}+\frac {7 c^{3/2} (5 b B-9 A c) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {b}}\right )}{8 b^{11/2}}\\ \end {align*}
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Mathematica [A]
time = 0.05, size = 140, normalized size = 1.00 \begin {gather*} -\frac {A}{5 b^3 x^5}-\frac {b B-3 A c}{3 b^4 x^3}+\frac {3 c (b B-2 A c)}{b^5 x}+\frac {c^2 (b B-A c) x}{4 b^4 \left (b+c x^2\right )^2}+\frac {c^2 (11 b B-15 A c) x}{8 b^5 \left (b+c x^2\right )}+\frac {7 c^{3/2} (5 b B-9 A c) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {b}}\right )}{8 b^{11/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.41, size = 119, normalized size = 0.85
method | result | size |
default | \(-\frac {c^{2} \left (\frac {\left (\frac {15}{8} A \,c^{2}-\frac {11}{8} b B c \right ) x^{3}+\frac {b \left (17 A c -13 B b \right ) x}{8}}{\left (c \,x^{2}+b \right )^{2}}+\frac {7 \left (9 A c -5 B b \right ) \arctan \left (\frac {c x}{\sqrt {b c}}\right )}{8 \sqrt {b c}}\right )}{b^{5}}-\frac {A}{5 b^{3} x^{5}}-\frac {-3 A c +B b}{3 b^{4} x^{3}}-\frac {3 c \left (2 A c -B b \right )}{b^{5} x}\) | \(119\) |
risch | \(\frac {-\frac {7 c^{3} \left (9 A c -5 B b \right ) x^{8}}{8 b^{5}}-\frac {35 c^{2} \left (9 A c -5 B b \right ) x^{6}}{24 b^{4}}-\frac {7 c \left (9 A c -5 B b \right ) x^{4}}{15 b^{3}}+\frac {\left (9 A c -5 B b \right ) x^{2}}{15 b^{2}}-\frac {A}{5 b}}{x^{5} \left (c \,x^{2}+b \right )^{2}}+\frac {7 \left (\munderset {\textit {\_R} =\RootOf \left (b^{11} \textit {\_Z}^{2}+81 A^{2} c^{5}-90 A B b \,c^{4}+25 B^{2} b^{2} c^{3}\right )}{\sum }\textit {\_R} \ln \left (\left (3 \textit {\_R}^{2} b^{11}+162 A^{2} c^{5}-180 A B b \,c^{4}+50 B^{2} b^{2} c^{3}\right ) x +\left (9 A \,b^{6} c^{2}-5 B \,b^{7} c \right ) \textit {\_R} \right )\right )}{16}\) | \(199\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.50, size = 154, normalized size = 1.10 \begin {gather*} \frac {105 \, {\left (5 \, B b c^{3} - 9 \, A c^{4}\right )} x^{8} + 175 \, {\left (5 \, B b^{2} c^{2} - 9 \, A b c^{3}\right )} x^{6} - 24 \, A b^{4} + 56 \, {\left (5 \, B b^{3} c - 9 \, A b^{2} c^{2}\right )} x^{4} - 8 \, {\left (5 \, B b^{4} - 9 \, A b^{3} c\right )} x^{2}}{120 \, {\left (b^{5} c^{2} x^{9} + 2 \, b^{6} c x^{7} + b^{7} x^{5}\right )}} + \frac {7 \, {\left (5 \, B b c^{2} - 9 \, A c^{3}\right )} \arctan \left (\frac {c x}{\sqrt {b c}}\right )}{8 \, \sqrt {b c} b^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.49, size = 426, normalized size = 3.04 \begin {gather*} \left [\frac {210 \, {\left (5 \, B b c^{3} - 9 \, A c^{4}\right )} x^{8} + 350 \, {\left (5 \, B b^{2} c^{2} - 9 \, A b c^{3}\right )} x^{6} - 48 \, A b^{4} + 112 \, {\left (5 \, B b^{3} c - 9 \, A b^{2} c^{2}\right )} x^{4} - 16 \, {\left (5 \, B b^{4} - 9 \, A b^{3} c\right )} x^{2} - 105 \, {\left ({\left (5 \, B b c^{3} - 9 \, A c^{4}\right )} x^{9} + 2 \, {\left (5 \, B b^{2} c^{2} - 9 \, A b c^{3}\right )} x^{7} + {\left (5 \, B b^{3} c - 9 \, A b^{2} c^{2}\right )} x^{5}\right )} \sqrt {-\frac {c}{b}} \log \left (\frac {c x^{2} - 2 \, b x \sqrt {-\frac {c}{b}} - b}{c x^{2} + b}\right )}{240 \, {\left (b^{5} c^{2} x^{9} + 2 \, b^{6} c x^{7} + b^{7} x^{5}\right )}}, \frac {105 \, {\left (5 \, B b c^{3} - 9 \, A c^{4}\right )} x^{8} + 175 \, {\left (5 \, B b^{2} c^{2} - 9 \, A b c^{3}\right )} x^{6} - 24 \, A b^{4} + 56 \, {\left (5 \, B b^{3} c - 9 \, A b^{2} c^{2}\right )} x^{4} - 8 \, {\left (5 \, B b^{4} - 9 \, A b^{3} c\right )} x^{2} + 105 \, {\left ({\left (5 \, B b c^{3} - 9 \, A c^{4}\right )} x^{9} + 2 \, {\left (5 \, B b^{2} c^{2} - 9 \, A b c^{3}\right )} x^{7} + {\left (5 \, B b^{3} c - 9 \, A b^{2} c^{2}\right )} x^{5}\right )} \sqrt {\frac {c}{b}} \arctan \left (x \sqrt {\frac {c}{b}}\right )}{120 \, {\left (b^{5} c^{2} x^{9} + 2 \, b^{6} c x^{7} + b^{7} x^{5}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.44, size = 260, normalized size = 1.86 \begin {gather*} - \frac {7 \sqrt {- \frac {c^{3}}{b^{11}}} \left (- 9 A c + 5 B b\right ) \log {\left (- \frac {7 b^{6} \sqrt {- \frac {c^{3}}{b^{11}}} \left (- 9 A c + 5 B b\right )}{- 63 A c^{3} + 35 B b c^{2}} + x \right )}}{16} + \frac {7 \sqrt {- \frac {c^{3}}{b^{11}}} \left (- 9 A c + 5 B b\right ) \log {\left (\frac {7 b^{6} \sqrt {- \frac {c^{3}}{b^{11}}} \left (- 9 A c + 5 B b\right )}{- 63 A c^{3} + 35 B b c^{2}} + x \right )}}{16} + \frac {- 24 A b^{4} + x^{8} \left (- 945 A c^{4} + 525 B b c^{3}\right ) + x^{6} \left (- 1575 A b c^{3} + 875 B b^{2} c^{2}\right ) + x^{4} \left (- 504 A b^{2} c^{2} + 280 B b^{3} c\right ) + x^{2} \cdot \left (72 A b^{3} c - 40 B b^{4}\right )}{120 b^{7} x^{5} + 240 b^{6} c x^{7} + 120 b^{5} c^{2} x^{9}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.94, size = 135, normalized size = 0.96 \begin {gather*} \frac {7 \, {\left (5 \, B b c^{2} - 9 \, A c^{3}\right )} \arctan \left (\frac {c x}{\sqrt {b c}}\right )}{8 \, \sqrt {b c} b^{5}} + \frac {11 \, B b c^{3} x^{3} - 15 \, A c^{4} x^{3} + 13 \, B b^{2} c^{2} x - 17 \, A b c^{3} x}{8 \, {\left (c x^{2} + b\right )}^{2} b^{5}} + \frac {45 \, B b c x^{4} - 90 \, A c^{2} x^{4} - 5 \, B b^{2} x^{2} + 15 \, A b c x^{2} - 3 \, A b^{2}}{15 \, b^{5} x^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.19, size = 135, normalized size = 0.96 \begin {gather*} -\frac {\frac {A}{5\,b}-\frac {x^2\,\left (9\,A\,c-5\,B\,b\right )}{15\,b^2}+\frac {35\,c^2\,x^6\,\left (9\,A\,c-5\,B\,b\right )}{24\,b^4}+\frac {7\,c^3\,x^8\,\left (9\,A\,c-5\,B\,b\right )}{8\,b^5}+\frac {7\,c\,x^4\,\left (9\,A\,c-5\,B\,b\right )}{15\,b^3}}{b^2\,x^5+2\,b\,c\,x^7+c^2\,x^9}-\frac {7\,c^{3/2}\,\mathrm {atan}\left (\frac {\sqrt {c}\,x}{\sqrt {b}}\right )\,\left (9\,A\,c-5\,B\,b\right )}{8\,b^{11/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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